WebSocket
Giả lập phản hồi 1002 Protocol Error
An endpoint is terminating the connection because it received data that violates the WebSocket protocol specification.
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HTTP/1.1 1002 Protocol Error Content-Type: application/json Date: Tue, 25 Feb 2026 12:00:00 GMT
2 Kiểm tra với curl
curl -i https://httpbin.org/status/1002
3 Trả về 1002 Protocol Error trong Framework của bạn
django
from django.http import HttpResponse
def my_view(request):
return HttpResponse(status=1002) # Protocol Error
flask
from flask import Flask
app = Flask(__name__)
@app.route("/endpoint")
def my_endpoint():
return "", 1002 # Protocol Error
fastapi
from fastapi import FastAPI
from fastapi.responses import Response
app = FastAPI()
@app.get("/endpoint")
def my_endpoint():
return Response(status_code=1002) # Protocol Error
express.js
// Express.js
app.get('/endpoint', (req, res) => {
res.sendStatus(1002); // Protocol Error
});
spring boot
import org.springframework.http.ResponseEntity;
import org.springframework.web.bind.annotation.*;
@RestController
public class MyController {
@GetMapping("/endpoint")
public ResponseEntity<Void> myEndpoint() {
return ResponseEntity
.status(1002) // Protocol Error
.build();
}
}
go net/http
package main
import "net/http"
func myHandler(w http.ResponseWriter, r *http.Request) {
w.WriteHeader(1002) // Protocol Error
}
ruby on rails
class MyController < ApplicationController
def my_action
head :protocol_error
end
end
asp.net core
// ASP.NET Core Minimal API
app.MapGet("/endpoint", () =>
Results.StatusCode(1002) // Protocol Error
);